Available online
Description
This programme looks at how all conic sections can be found as slices of some cone and are therefore perspectively equivalent. This result is used to prove a theorem in 2-dimensional geometry.
This programme looks at how all conic sections can be found as slices of some cone and are therefore perspectively equivalent. This result is used to prove a theorem in 2-dimensional geometry.
| Module code and title: | M203, Introduction to pure mathematics |
|---|---|
| Item code: | M203; 05E |
| First transmission date: | 1995 |
| Published: | 1995 |
| Rights Statement: | |
| Restrictions on use: | |
| Duration: | 00:24:02 |
| + Show more... | |
| Producer: | Jean Nunn |
| Contributors: | Roberta Cheriyan; Jeremy Gray |
| Publisher: | BBC Open University |
| Keyword(s): | Asymptotes; Ceva's theorem; Eccentricity; Ellipse; Generator; Hyperbola; Parabola; Projective transformation; Projectively equivalent; Section |
| Subject terms: | Conic sections; Conics, Spherical |
| Footage description: | The programme focuses on the theorem that with any conic and any tangent triangle to it the construction joining each vertex of the triangle to the opposite point of tangency produces three lines that meet in a point. The proof involves two things a) the investigation of conies as slices of a cone and consequently b) the projective equivalence of all conics. Computer animations are used to explore how changing the angle of intersection of a plane with a cone produces ellipses, parabolas and hyperbolas, depending on the relation between the angle of the slice and the angle of the cone. But given the freedom to chose the angle of the cone and the position of the slice any two conics can be found as slices of one cone and therefore all conics are protectively equivalent. The therorem is then proved for a circle, using the converse of Ceva's theorem, and so holds true for all other conics. |
| Master spool number: | DOU7934 |
| Production number: | FOUM454L |
| Videofinder number: | 4647 |
| Available to public: | no |
